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Re: rho vs. rho +/- 1 (esp. for computePressureField())


Mathias,rnrnThank you again for your patience.rnrnI think you and I are missing an important point…rnrnblock.get(iX,iY).computeRho() computes the fluid’s actual RHO not (RHO + 1).rnrnUsing the actual RHO for the fluid, your computed pressure is (I think incorrectly)…rnrnP = (RHO – 1) * (Cs*Cs)rnrnI don’t think this is what you want.rnrnRegards,rnRandyrn