Re: rho vs. rho +/- 1 (esp. for computePressureField())
Due to recent bot attacks we have changed the sign-up process. If you want to participate in our forum, first register on this website and then send a message via our contact form.
› Forums › OpenLB › General Topics › rho vs. rho +/- 1 (esp. for computePressureField()) › Re: rho vs. rho +/- 1 (esp. for computePressureField())
July 30, 2013 at 3:22 pm
#2112
Randy Roberts
Member
Mathias,rnrnThank you again for your patience.rnrnI think you and I are missing an important point…rnrnblock.get(iX,iY).computeRho() computes the fluid’s actual RHO not (RHO + 1).rnrnUsing the actual RHO for the fluid, your computed pressure is (I think incorrectly)…rnrnP = (RHO – 1) * (Cs*Cs)rnrnI don’t think this is what you want.rnrnRegards,rnRandyrn