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Re: rho vs. rho +/- 1 (esp. for computePressureField())

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› Forums › OpenLB › General Topics › rho vs. rho +/- 1 (esp. for computePressureField()) › Re: rho vs. rho +/- 1 (esp. for computePressureField())

July 30, 2013 at 3:47 pm #2113
mathias
Keymaster

Hi,rnrnI understand. Sorry for confusing you. By doing it the way “”P = (RHO – 1) * (Cs*Cs)”” you obtain “”P=0″” for “”RHO=1″”. If you dont do that scaling, you will get different “”pressure levels”” for different discretisations. Then, with the help of the unit converter you can add any constant “”pressure level”” you want. rnrnMathias