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Re: rho vs. rho +/- 1 (esp. for computePressureField())


Hi,rnrnI understand. Sorry for confusing you. By doing it the way “”P = (RHO – 1) * (Cs*Cs)”” you obtain “”P=0″” for “”RHO=1″”. If you dont do that scaling, you will get different “”pressure levels”” for different discretisations. Then, with the help of the unit converter you can add any constant “”pressure level”” you want. rnrnMathias