Re: rho vs. rho +/- 1 (esp. for computePressureField())
Due to recent bot attacks we have changed the sign-up process. If you want to participate in our forum, first register on this website and then send a message via our contact form.
› Forums › OpenLB › General Topics › rho vs. rho +/- 1 (esp. for computePressureField()) › Re: rho vs. rho +/- 1 (esp. for computePressureField())
June 28, 2013 at 4:10 pm
#2105
Randy Roberts
Member
Correction:rn I meant for the c^2 term to be multiplied, not divided. rnrnCorrected question 2)…rnrn2) Why is pressure calculated the way it is (shown below)? Isn’t the equation of staternp = rho*c^2,rnnotrnp = (rho-1)*c^2rn
