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D2Q9 TRT Lid driven cavity flow

This topic contains 2 replies, has 2 voices, and was last updated by  Alex 2 months ago.

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    I finished the solution of D2Q9 BGK Lid driven cavity flow and now start the TRT collision operator approximation. I used several papers and book of Mohamad about LBM. If i understand correctly, I need to modify only collision step. I split distribution function into symmetric and asymmetric parts. tau_symmetric is calculated as ( 3*nu_lb + 0.5 ), tau_asymmetric = 0.5*tau_s/(tau_s-0.5) [magic paramter = 0.25]. With this parameters the code is unstable. Notably, when tau_asymmetric = tau_symmetric i have BGK solution, as it should be. So i think the problem is in calculation of tau_asymmetric. The relevant part of the code is as follows:

    opposite=[1 4 5 2 3 8 9 6 7];
        t1 = u.*u + v.*v;
        for k = 1:9
     t2 = cx(k)*u + cy(k)*v;
            feq(:,:,k) = w(k)*rho.*(1 + 3*t2 + 4.5*t2.^2 - 1.5*t1);

    Can someone suggest any guides or help me with this problem?
    Thanks a lot!



    Hi Alex

    Your implementation seems to be correct. Also the fact that setting \tau_s = \tau_a yields the BGK solution is a good sign.

    The specific values for the magic parameter \Lambda = (\tau_s – 0.5)*(\tau_a – 0.5) mentioned in the literature are a typical result for certain flow types and Reynolds number regimes.

    If your code is supposed to run at high Reynolds numbers, I suggest you try different (smaller or much smaller) values for \Lambda, since it is connected to the Reynolds number via \tau_s. For high Reynolds numbers, the magnitude of \tau_a is way too large with a fixed \Lambda=0.25. Maybe try a few decimal digits below that, e.g. \Lambda=0.0025 and work your way up.

    With the calibration of \tau_a through a smaller \Lambda, you should obtain stable results. In case this does not work, fix \tau_a=1 and try again.

    If you encounter any special results (highly increased stability, or none at all), please let me know.

    Anyway, good luck with your tests.


    PS: A similar question was posted and answered about two month ago:



    Hello Stephan,

    Thank you! I will try it

    kind regards,

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